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X^2-6.4X+5=0
a = 1; b = -6.4; c = +5;
Δ = b2-4ac
Δ = -6.42-4·1·5
Δ = 20.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.4)-\sqrt{20.96}}{2*1}=\frac{6.4-\sqrt{20.96}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.4)+\sqrt{20.96}}{2*1}=\frac{6.4+\sqrt{20.96}}{2} $
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